Answer:
f'(x) = -6/x³
Step-by-step explanation:
We are given;
f(x) = 3/x²
Using quotient rule, we can write as;
f(x) = g(x)/h(x)
To find the derivative, from quotient rule, we can write;
f'(x) = [(h(x)*g'(x)) - (g(x)*h'(x))]/(h(x))²
g'(x) = 0
h'(x) = 2x
Thus;
f'(x) = [(x²*0) - (3*2x)]/(x²)²
f'(x) = -6x/x⁴ = -6/x³
f'(x) = -6/x³
