121267 121267
  • 07-12-2020
  • Chemistry
contestada

How many atoms are in 18.99g of fluorine?

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al3x45
al3x45 al3x45
  • 07-12-2020

18.99g/mol F = 1 mole of F

1 mole is equal to Avogadro's number which is:

[tex]6.02214076 × {10}^{23} [/tex]

Therefore, one mole of fluorine has 6.02214076 × 10^23 fluorine atoms.

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nadia2318116
nadia2318116 nadia2318116
  • 07-12-2020

Answer:

Explanation:

The Molar mass of fluorine= 18.99

Moles=mass/molar mass=18.99/18.99=1

Numbers of atoms=1x6.02x10^23=6.02x10^23

I hope it helps

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