Respuesta :

Answer:

  2.318·10^6

Explanation:

You want to find k such that ...

  e^-k = (1/2)^(1/(299·10^-9))

  -k = ln(1/2)/(299·10^-9)

  k = ln(2)/(299·10^-9) ≈ 2.318·10^6

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