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  • 06-12-2020
  • Mathematics
contestada

write the equation of a line is perpendicular to the line y=2/3x-4 and passes through the point (6,3) in slope intercept form and point slope form

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xenia168
xenia168 xenia168
  • 06-12-2020

Answer:

y = - [tex]\frac{3}{2}[/tex] x + 12

Step-by-step explanation:

y = [tex]\frac{2}{3}[/tex] x - 4

(6, 3)

y - 3 = - [tex]\frac{3}{2}[/tex] (x - 6)

y = - [tex]\frac{3}{2}[/tex] x + 12

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