Given :
Angle of elevation, Ф = 24°.
Distance of Sam from launchpad, D = 5 miles.
To Find :
How high is the rocket.
Solution :
Let, height is h.
We know, tan Ф is given by :
[tex]tan \ \phi=\dfrac{h}{d}\\\\tan \ 24^{\circ}=\dfrac{h}{5}\\\\h = 5\times tan \ 24^{\circ}\\\\h = 2.226 \ miles[/tex]
Hence, this is the required solution.
