Answer:
x = 7
Step-by-step explanation:
[tex]2log_5(x-3)-log_58= log_52\\\\
2log_5(x-3) =log_52+log_58\\\\
2log_5(x-3) =log_5(2\times 8) \\\\
2log_5(x-3) =log_516\\\\
2log_5(x-3) =log_54^2 \\\\
2log_5(x-3) =2 log_54 \\\\
log_5(x-3) =log_54 \\\\
x - 3 = 4\\\\
x = 4+3\\\\
\huge \orange { \boxed{x = 7}}
[/tex]
