Given:
Length of rectangle = (x+10) cm
Width of the rectangle = x cm
Perimeter = 32 cm
To find:
The length of the rectangle.
Solution:
We know that,
[tex]Perimeter=2(l+w)[/tex]
Where, l is length and w is width.
Substituting the values, we get
[tex]32=2((x+10)+x)[/tex]
[tex]32=2(2x+10)[/tex]
[tex]32=4x+20[/tex]
Subtract 20 from both sides.
[tex]32-20=4x[/tex]
[tex]12=4x[/tex]
Divide both sides by
[tex]3=x[/tex]
So, the length is
[tex]3+10=13[/tex]
Therefore, the length of the rectangle is 13 cm.
