Idea63
Idea63 Idea63
  • 09-11-2020
  • Mathematics
contestada

On interval 0 ≤ x < 2π, where are the x-intercepts of y = cos(2x)?

On interval 0 x lt 2π where are the xintercepts of y cos2x class=

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jimthompson5910 jimthompson5910
  • 09-11-2020

The answer is choice D because we plug in something like x = pi/4 and it leads to

y = cos(2x)

y = cos(2*pi/4)

y = cos(pi/2)

y = 0

Use the unit circle to see why cos(pi/2) = 0.

Since we get y = 0 as a result, this shows x = pi/4 is one of the x intercepts.

You'll also get y = 0 if you plug in x = 3pi/4, x = 5pi/4, and x = 7pi/4. All of these values are on the interval [tex]0 \le x < 2\pi[/tex]

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brownkaitlyn697 brownkaitlyn697
  • 09-11-2020

Answer:

The Answer is D thanks!

Step-by-step explanation:

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