The given function is
[tex]h(x) = \{ (0,1), (2,3), (-4, 1) \}[/tex]
The inverse function is
[tex]h^{-1}(x) = \{ (1,0), (3,2), (1,-4)\}[/tex]
To get the inverse, we swap each x and y coordinate.
The rule is [tex](x,y) \to (y,x)[/tex]
So that's why the point (0,1) becomes (1,0) for instance.
