Answer:
pH = 1.05
Explanation:
A solution of sulfuric acid, H₂SO₄, dissociates in water as follows:
H₂SO₄ → 2H⁺ + SO₄²⁻
That means per mole of H₂SO₄ you will have 2 moles of H⁺
pH = -log [H⁺]
As [H₂SO₄] = 0.045M and [H⁺] = 2×[H₂SO₄]
[H⁺] = 0.090M
pH = -log [0.090M]
pH = 1.05
