Answer:
the velocity is 10.6m/s
the time taken is 1.5sec
Explanation:
height (h)=61m
from,
[tex] {v}^{2} = 2gh[/tex]
v^2 = 2 (10)(61)
v^2 = 1220
v^2 = 10.6m/s
for time
[tex]v = \frac{1}{2} g {t}^{2} [/tex]
v=10.6
10.6=1×10t^2/2
10.6=5t^2
10.6/5=5t^2/5
t^2=2.12
t=1.5sec
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