Answer:
[tex]x=-3[/tex]
Step-by-step explanation:
[tex]\frac{2}{3}\left(3x+9\right)=-2\left(2x+6\right)[/tex]
Expand:
[tex]\frac{2}{3} *3x+\frac{2}{3} *9=-2*2x+(-2)(6)[/tex]
[tex]2x+6=-4x-12[/tex]
Subtract 6 from both sides:
[tex]2x+6-6=-4x-12-6[/tex]
[tex]2x=-4x-18[/tex]
Add 4x to both sides:
[tex]2x+4x=-4x-18+4x[/tex]
[tex]6x=18[/tex]
Divide both sides by 6:
[tex]\frac{6x}{6}=\frac{-18}{6}\\[/tex]
[tex]x=-3[/tex]
