yaboityler73 yaboityler73

10-09-2020
Chemistry

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What volume is occupied by 0.25 moles of nitrogen gas at 273 K and 1.50 atm.

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kinsondols186 kinsondols186

10-09-2020

Answer:

3.74L

Explanation:

PV=nRT

V=nRT/P

= 0.25mol*0.0821LatmK^-1*273k/1.50atm

=3.74L

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