Answer:
[tex] \boxed{\sf A. \ x = 10 \degree} [/tex]
Given:
∠AOC = 90°
∠AOB = 3x° + 46°
∠BOC = 14°
To Find:
Value of x
Step-by-step explanation:
∠AOC = ∠AOB + ∠BOC
90° = 3x° + 46° + 14°
90° = 3x° + 60°
3x° + 60° = 90°
3x° = 90° - 60°
3x° = 30°
x = [tex] \sf \dfrac{30}{3} [/tex]°
x = 10°
