Answer:
C
Step-by-step explanation:
Given
9 { [tex]\frac{x}{3}[/tex] + 1 } ≥ 6 ( divide both sides by 9 )
[tex]\frac{x}{3}[/tex] + 1 ≥ [tex]\frac{6}{9}[/tex] , that is
[tex]\frac{x}{3}[/tex] + 1 ≥ [tex]\frac{2}{3}[/tex] ( multiply through by 3 to clear the fractions )
x + 3 ≥ 2 ( subtract 3 from both sides )
x ≥ - 1 → C
