nusaibamaria321
nusaibamaria321 nusaibamaria321
  • 07-09-2020
  • Physics
contestada

If a 8.0 kg mass is hung on the end of a spring, it is stretched 0.78 meters as a result. What is the force constant of the spring?

Respuesta :

kawog31408 kawog31408
  • 07-09-2020

Answer:

[tex]K=100.62N/m[/tex]

Explanation:

Given:

             [tex]m= 8.0 Kg\\x=0.78 m[/tex]

We know from Hook's law

           [tex]F= k x[/tex]

where

           [tex]F= m g[/tex]

So equating we get

             [tex]mg=kx\\k=\frac{mg}{x} \\k=\frac{8*9.8}{0.78}\\k=100.62 N/m[/tex]

Answer Link
askboutalexx
askboutalexx askboutalexx
  • 15-09-2020

Answer:

k=100.5 n/m

Explanation:

Answer Link

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