In triangle ABC, the size of angle B is 4 times the size of angle A, and the size of angle C is 2° less than 5 times
the size of angle A.

Find the size of the angles.

Respuesta :

Answer:

4x + x +(5x-2°) = 180°

10X - 2° = 180°

10x = 180° + 2°

x = 182°/ 10

x = 18.2°

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