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Working with BPDS (Basic Principle for Differences of Squares), apply the Fermat factorization method to factor 5959.

Respuesta :

Answer: 101 and 59

Step-by-step explanation:

Rewrite as a difference of 2 perfect squares

5959 = (6400-441) = (80)^2 - (21)^2

Difference of 2 perfect squares

a^2 - b^2 = (a+b) (a-b)

Factors are (80+21) and (80-21)

101 and 59

saraibryant5
101 and I believe 59

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