Answer:
48.00 microamps
Explanation:
The base voltage is limited by the zener to 5.5 V. If we assume the B-E voltage drop is 0.7 V, then the voltage across RE is 5.5-0.7 = 4.8 volts. That means the emitter current is 4.8/2.0k = 2.4 mA.
The base current is that amount divided by (1+β), so is 2.4 mA/(1+49) = 48 μA.
