Explanation:
The asked in the Question is missing, although i am assuming the number
as [tex]\frac{6}{23}[/tex] ÷[tex]\frac{\sqrt{2} }{2}[/tex].
The given expression contains an irrational number. So, the quotient will also be an irrational number.
Solving
[tex]\frac{6}{23}\times\frac{\sqrt{2} }{2} \\=\frac{3\sqrt{2} }{23}[/tex]
Which is an irrational number.
