zoiebrown4704 zoiebrown4704
  • 07-08-2020
  • Chemistry
contestada

When the nuclide carbon-14 undergoes beta decay: The name of the product nuclide is . The symbol for the product nuclide is

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lawalj99 lawalj99
  • 08-08-2020

Answer:

Explanation:

The equation for the decay is given as;

¹⁴₆C  --> X + ⁰₋₁e

For conservation of matter, the mass number and atomic number has to be the same in both the reactant and product side f he equation;

Mass number;

14 = x + 0

x = 14

Atomic Number;

6 = x + (-1)

x = 6 + 1 =7

¹⁴₆C  --> ¹⁴₇N + ⁰₋₁e

The name of the product nuclide with atomic number of 7 is Nitrogen. The symbol is; ¹⁴₇N

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