If the nth term is nn+1, then the (n+1)st term is:
Answer:
[tex]\large \boxed{\sf C. \ (n+1)^{n+1}+1}[/tex]
Step-by-step explanation:
[tex]n^n+1[/tex]
Plug in the value for n as n+1 in the nth term to find the (n+1)st term.
[tex](n+1)^{n+1}+1[/tex]