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06-08-2020
Physics

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A 10kg block with an initial velocity of 10 m/s slides 1o m across a horizontal surface and comes to rest. it takes the block 2 seconds to stop. The stopping force acting on the block is about

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Percivle Percivle

06-08-2020

Answer:

-50N

Explanation:

F=ma=m(Vf-Vi)/t

m=10kg
Vf=0m/s
Vi=10m/s
t=2s

F=(10)(-10)/(2)=-50N

So the force acting on the block is -50N, where the negative sign simply tells us that the force is opposite to the direction of movement.

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