Respuesta :

gloriagyamfuaa399

Answer:

X^2 +Y^2 - 2X-4Y= 0

Step-by-step explanation:

From the circle eqn.

(x-a) ^2 +(y-b) ^2 =r^2

a=1, b= 2. r= 3

(x-1)^2 +(y-2)^2 =3^2

(x-1)(x-1)+(y-2)(y-2)=3^2

X^2 - 2x+1+y^2 -4y+4=9

X^2 +Y^2 - 2x-4y+5=9

X^2 +Y^2 - 2x-4y-4=0