Respuesta :

dalendrk
[tex]\dfrac{4(3h-6)}{1+h}\\\\h=-2,\ subtitute\\\\\dfrac{4[3\cdot(-2)-6]}{1+(-2)}=\dfrac{4(-6-6)}{1-2}=\dfrac{4\cdot(-12)}{-1}=\dfrac{-48}{-1}=48[/tex]
SuperLegend
4(3h-6)/1+h
Substitute 2 for all of the h.
4(3(2)-6)/1-2
Multiply the number outside the parenthesis with the numbers inside the parenthesis. 
(12(8)-24)/1-2
Multiply 8 by 12
96-24/1+2
Divide 24 by 1
96-24-2
Subtract 24 from 96
72-2
Add
Final Answer: 70

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