ngprudente299 ngprudente299

09-07-2020
Physics

contestada

While working out, a man performed 2525 J of work in 19 seconds. What was
his power?

Respuesta :

senalfernando111 senalfernando111

09-07-2020

Answer:

[tex]power = \frac{work \: done}{time \: passed} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

power=2525J/19S

=132.8947368421JS^-1

=132.9W

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