Answer: x = 1, y = -3
Explanation: Use the method of substitution we get:
y = x^2-4
y = 2x-5
By substitute:
x^2-4=2x-5
Then we can solve the equation for x
x^2-4-2x+5=0
x^2-2x+1=0
Now solve the quadratic equation by factoring we get:
x^2-2x+1=0
(x-1)(x-1)=0
x-1=0
x = 1
Now that we have found x we can substitute x to the equation:
y = x^2-4
y=1^2-4
y=-3
y=2x-5
y=2(1)-5
y=-3
So there you have it :)
