Answer:
3.46
Explanation:
Hello,
This question can be solved using Henderson-Hasselbalch equation.
The dissociation equation of acetic acid in water is
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺
pH = pKa + log([conjugate base] / [weak acid])
Conjugate base = acetic acid
Weak acid = water
pKa = 4.76
pH = 4.76 + log([0.05]/[1])
pH = 4.76 + log(0.05)
pH = 4.76 + (-1.30)
pH = 3.46
From the above solution, the pH of the solution is 3.46
