Answer:
Last option
Step-by-step explanation:
Since we can't factor out the quadratic, we need to use quadratic formula to solve this: [tex]x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}[/tex]
a = 5
b = -2
c = 6
[tex]x = \frac{2 +/- \sqrt{(-2)^2 - 4(5)(6)} }{2(5)}[/tex]
[tex]x = \frac{2 +/- \sqrt{4 - 120} }{10}[/tex]
[tex]x = \frac{2 +/- \sqrt{-116} }{10}[/tex]
[tex]x = \frac{2 +/- 2i\sqrt{29} }{10}[/tex]
[tex]x = \frac{1 +/- i\sqrt{29} }{5}[/tex]
