Answer:
[tex]-12-10i[/tex] is the required answer.
Step-by-step explanation:
[tex]\left(-9-8i\right)-\left(3+2i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\\=\left(-9-3\right)+\left(-8-2\right)i\\\\=-12-10i[/tex]
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