marquezclaxton22
marquezclaxton22 marquezclaxton22
  • 06-07-2020
  • Mathematics
contestada

Please help I need it

Please help I need it class=

Respuesta :

mani82ebra
mani82ebra mani82ebra
  • 06-07-2020

Answer:

[tex] \frac{1}{3} [/tex]

Step-by-step explanation:

so

just consider the lengh:

[tex] \frac{1}{3} [/tex]

or the width :

[tex] \frac{3}{9} [/tex]

or the area:

[tex] \sqrt{ \frac{3 \times 1}{9 \times 3} } = \sqrt{ \frac{3}{27} } = \sqrt{ \frac{1}{9} } = \frac{1}{3} [/tex]

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