Answer:
The new force becomes 3 times of the initial force.
Explanation:
Let q₁ and q₂ are two charged particles. The force between them is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\ ......(1)[/tex]
If [tex]q_1'=\dfrac{q_1}{4}[/tex]
and
[tex]q_2'=3q_2[/tex]
Also, r' = r/2
New force,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]
Putting all the above values,
[tex]F'=\dfrac{k\dfrac{q_1}{4}3q_2}{(r/2)^2}\\\\F'=3\times \dfrac{kq_1q_2}{r^2}\\\\F'=3F[/tex]
So, the new force becomes 3 times of the initial force.
