mollyhaydens
mollyhaydens mollyhaydens
  • 10-06-2020
  • Mathematics
contestada

What is the vertex of the graph of the function f(x) = x2 + 8x - 2?
(-4, 18)
(0, -2)
O (-8,-2)
O (-4, -18)

Respuesta :

jimrgrant1 jimrgrant1
  • 10-06-2020

Answer:

vertex = (- 4, - 18 )

Step-by-step explanation:

Given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

The the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

f(x) = x² + 8x - 2 ← is in standard form

with a = 1 and b = 8 , thus

[tex]x_{vertex}[/tex] = - [tex]\frac{8}{2}[/tex] = - 4

Substitute x = - 4 into f(x) for corresponding y- coordinate

f(- 4) = (- 4)² + 8(- 4) - 2 = 16 - 32 - 2 = - 18

vertex = (- 4, - 18 )

Answer Link
someoneunknown10
someoneunknown10 someoneunknown10
  • 24-06-2020

Answer:

(−4, −18)

Step-by-step explanation:

D on edg

Answer Link

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