Answer:
[tex]\dfrac{5\pm\sqrt{47}}{6}[/tex]
Step-by-step explanation:
Let's start by setting y to 0 to find the roots of the quadratic.
[tex]x=\dfrac{5\pm \sqrt{25+12}}{6}=\\\\\dfrac{5\pm\sqrt{47}}{6}[/tex]
Hope this helps!
