N
a
2
S
O
4
(
a
q
)
+
B
a
(
N
O
3
)
2
(
a
q
)
→
B
a
S
O
4
(
s
)
+
2
N
a
N
O
3
(
a
q
)
Break up the compounds into ions from which they came and cross out the ones that appear on both sides; those are your
spectator ions
.
2
N
a
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
+
2
N
a
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
Barium sulfate
is insoluble so it doesn't ionize in solution
Write net ionic equation
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
