The sum of all andles in quadrilateral is equal to 360°, so
[tex]5x - 30 + 60 - x + 3x + 60 + 4x + 50 = 360 \\ 11x = 220 \\ x = 20[/tex]
Now we need to put x into polynomials
1)
[tex]5 \times 20 - 30 = 70[/tex]
2)
[tex]60 - 20 = 40[/tex]
3)
[tex]3 \times 20 + 60 = 120[/tex]
4)
[tex]4 \times 20 + 50 = 130[/tex]
Answer: the smallest ahgle is 60-x
