Answer:
3.89 atm
Explanation:
Given data
- Initial pressure (P₁): 2.80 atm
- Initial temperature (T₁): 285 K
- Initial volume (V₁): 15.6 L
- Final temperature (T₂): 396 K
- Final volume (V₂): 15.6 L (=V₁)
If we treat air as an ideal gas, we can calculate the final pressure using the Gay-Lussac's law.
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}\\P_2 = \frac{P_1 \times T_2 }{T_1} = \frac{2.80atm \times 396K }{285K}\\P_2 = 3.89 atm[/tex]
