Answer:
[tex]P_2=\frac{1}{2} \text{ atm}[/tex]
Explanation:
Considering ideal gas situation and initial condition as 1 and final condition as 2 all other conditions being constant we get
[tex]P_1V_1=P_2V_2[/tex]
Here P1 = 1 atm , V1= 75L, also, V2=2V1 = 2×75 L =150 L
using above equation we have
[tex]1\times75=150\times P_2\\P_2=\frac{75}{150} = \frac{1}{2} \text{ atm}[/tex]
