Answer:
12.64 cm^3 to the nearest hundredth
Explanation:
1 L of 0.25M of HCl contains 0.25 * (1.008 * 35.45) g of HCl
= 9.1145 g HCl.
So 2 litres contain 18.229 g HCl.
So we need the volume of concentrated acid which contains 18.229 g HCl.
1.46 * 0.98 = 1.4308 g are in 1 cm^3
So 18.229 g are in 18.229/1.4308
= 12.6404 cm^3 (answer).
