sissakinzaly05
sissakinzaly05
08-08-2016
Mathematics
contestada
In ΔABC, what is the value of cos B?
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Ckaranja
Ckaranja
13-08-2016
[tex] b^{2} = a^{2} + c^{2} -2acCosB[/tex]
Making cos B the subject;
2acCosB=[tex] a^{2} + c^{2} - b^{2} [/tex]
cosB=[tex] \frac{ a^{2} + c^{2} - b^{2} }{2ac} [/tex]
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