meerkat18
meerkat18 meerkat18
  • 08-08-2016
  • Mathematics
contestada

If ON = MN, find MN.

If ON MN find MN class=

Respuesta :

dalendrk
dalendrk dalendrk
  • 08-08-2016
Use Pythagorean theorem.

[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}

Answer: |MN| = 4√2.
Answer Link
oozebumpz
oozebumpz oozebumpz
  • 10-02-2021

Answer:

C. 4 square root 2

Step-by-step explanation:

Answer Link

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