daluzirriyachpadga daluzirriyachpadga

07-08-2016
Mathematics

contestada

y = sec θ tan θ differentiate

Respuesta :

Hussain514 Hussain514

10-08-2016

Y = sec(θ) tan(θ).
Solution:
We use here the product rule that is
(fg) 0 = f 0 g + fg0 .
So
y 0 = (sec(θ) tan(θ)) tan(θ) + sec(θ) tan2 (θ)
= sec(θ)(tan2 (θ) + sec2 (θ)).

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