The value of sine of angle Q is 1.16
Explanation:
Given:
ΔQRS is a right angle triangle
∠S = 90°
QS = 33
SR = 56
QR = 65
Sin(∠Q) = ?
We know:
[tex]sin \alpha = \frac{perpendicular}{hypotenuse}[/tex]
So,
[tex]sin(Q) = \frac{QR}{RS} \\\\Sin (Q) = \frac{65}{56} \\\\sin (Q) = 1.16[/tex]
Therefore, the value of sine of angle Q is 1.16
