Find the surface area of a square pyramid with side length 1 m and slant height 5 m.
Answer:
A= 11.05
Step-by-step explanation:
A=a2+2a [tex]\sqrt{\frac{a^{2} }{4} } +h^{2}=1^{2} +2 (1)\sqrt{\frac{1^{2} }{4} } 5^{2} =11.04988[/tex]