Answer:
[tex]h=\sqrt{106} \approx 10.3[/tex] feet
Step-by-step explanation:
We will use the Pythagorean Theorem to solve this. Which states that:
One Length^2 + Another Length^2 = Hypotenuse^2
We can take one length as 5 ft and another length as 9 ft and we call the hypotenuse "h", so we have:
[tex]5^2+9^2=h^2[/tex]
Now, let us solve for "h":
[tex]5^2+9^2=h^2\\25 + 81 = h^2\\106=h^2\\h=\sqrt{106} \approx 10.3[/tex]
The pond's hypotenuse is about 10.3 feet
