answer and explain the picture above pls
Answer:
Step-by-step explanation:
[tex]1-\frac{sin^{2}A}{tan^{2}A}=1-\frac{sin^{2}A}{\frac{sin^{2}A}{cos^{2}A}}\\\\=1-sin^{2}A*\frac{cos^{2}A}{sin^{2}A}\\\\=1-cos^{2}A\\\\=sin^{2}A[/tex]