Solve the system of equations.
2x+3y= 6
х+у= 4
A (6,-2)
B (-2, 6).
C (-3, 4)
D (0, 2)

Question

07-03-2020
Mathematics

contestada

Solve the system of equations.
2x+3y= 6
х+у= 4
A (6,-2)
B (-2, 6).
C (-3, 4)
D (0, 2)

Respuesta :

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ProfessorAlvarez ProfessorAlvarez · Answer 1 · 2020-03-07T16:27:25+01:00

ProfessorAlvarez ProfessorAlvarez

07-03-2020

[tex]\text{Solve the systems of equations}\\\\2x+3y= 6\\\\x+y=4\\\\2x+3y= 6\\\\-2(x+y=4)\\\\2x+3y= 6\\\\-2x-2y=-8\\\\y=-2\\\\\text{Plug in -2 to the y value in one of the equations}\\\\x-2=4\\\\x=6\\\\\boxed{x=6\,\,y=-2}\\\\\boxed{(6,-2)}[/tex]

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Solve the system of equations. 2x+3y= 6 х+у= 4 A (6,-2) B (-2, 6). C (-3, 4) D (0, 2)

Respuesta :

Otras preguntas

Solve the system of equations.
2x+3y= 6
х+у= 4
A (6,-2)
B (-2, 6).
C (-3, 4)
D (0, 2)