Answer:
2x^2+8x-10
Step-by-step explanation:
we factorize each parentheses alone so
(x+2)(x-3)
(x+4)(x+5)
(x+2)(x-3)=
[tex] {x}^{2} - 3x + 2x - 6[/tex]
(x+4)(x+5)=
[tex] {x}^{2} + 5x +4x + 20[/tex]
so we add them together
x^2-3x+2x-6+x^2+5x+4x+20-24
2x^2+8x+14-24
2x^2+8x-10
