Answer:
Therefore either a:b = 5:4 or a:b=-5:4
Step-by-step explanation:
ax²-5bx+4a=0
Since the quadratic equation has two real root.
Then b²-4ac>0
Here a= a , b= -5b and c=4a
∴(-5b)²-4.a.4a=0
⇔25b²=16a²
⇔5b=±4a
[tex]\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}[/tex]
Therefore either a:b = 5:4 or a:b=-5:4
