19 g of K₂SO₄ was produced.
Explanation:
2 KOH + H₂SO₄ →K₂SO₄ + 2 H₂O
Now if we have 10.75 g of H₂SO₄ we can calculate the number of moles as,
Wt / M.wt = 10.75 / 98 = 0.109 moles
Now we can calculate the number of moles of K₂SO₄ as that:
1 mole of H₂SO₄react gives 1 mole K₂SO₄
0.109 mole of H₂SO₄ gives (x)
x (number of moles of K₂SO₄ = 1 × 0.109 / 1 = 0.109 mole
now we can calculate the wt as,
wt = no. moles × M.wt
wt = 0.109 × 174.259 = 18.966 g = 19 g
